Question

Плиз помоги те пожалуйста

Answer 1

Решение:

$9 - (1\frac{5}{8} + \frac{3}{20})\\\\9 - (1\frac{5*5}{8*5} + \frac{3*2}{20*2})\\\\9 - (1\frac{25}{40} + \frac{6}{40})\\\\9 - (1\frac{31}{40})\\\\9 - 1\frac{31}{40}\\\\8\frac{40}{40} - 1\frac{31}{40}\\\\(8-1)\frac{40-31}{40}\\\\7\frac{9}{40}$