Question

Производная dy\dx функции {x=ln4t; y=1\2t, заданной параметрически, равна

Answer 1

Ответ:

$y'x = \frac{y't}{x't}$

$y't = \frac{1}{2} \times (-{t}^{-2}) =-\frac{1}{2{t}^{2}}\\ x't = \frac{1}{4t} \times 4 = \frac{1}{t}$

$y'x = -\frac{1}{2{t}^{2}} \times t = - \frac{1}{2t}$