Question

Помогите пожалуйста решить, корни ​

Answer 1

Ответ:

а)70;

б)60

в)36

г)120

Объяснение:

а)√(50*98)=

=√(2*5*5*2*7*7)=√(2²*5²*7²)=

=2*5*7=70

б)√(360*10)=

=√(6*6*10*10)=√(6²*10²)=

=6*10=60

в)√(48*27)=

=√(4*4*3*3*3*3)=√(4²*3²*3²)=

=4*3*3=36

г)√(30*480)=

=√(3*10*10*3*4*4)=√(3²*10²*4²)=

=3*10*4=120

Answer 2

$1)\sqrt{50*98}=\sqrt{25*2*49*2}=\sqrt{5^{2}*7^{2}*2^{2}}=5*7*2=\boxed{70}\\\\2)\sqrt{360*10}=\sqrt{36*10*10}=\sqrt{6^{2}*10^{2}}=6*10=\boxed{60}\\\\3)\sqrt{48*27}=\sqrt{16*3*9*3}=\sqrt{4^{2}*3^{2}*3^{2}}=4*3*3=\boxed{36}\\\\4)\sqrt{30*480} =\sqrt{30*30*16}=\sqrt{30^{2}*4^{2}} =30*4=\boxed{120}$