Question

3 sin ^ 2 x - cos ^ 2 x - 1 = 0
Решите уравнение

Answer 1

$3 \ {sin}^{2} x - {cos}^{2} x - 1 = 0 \\ 3 {sin}^{2} x - 1 + {sin}^{2} x - 1 = 0 \\ 4 {sin}^{2} x = 2 \\ {sin}^{2} x = \frac{1}{2} \\ sinx = + - \frac{ \sqrt{2} }{2} \\ x = \frac{\pi}{4} + \frac{\pi}{2} n \:$

n є Z