Question

3х*(х-4)=28-7х
Сколько ето будет

Answer 1

$3x(x-4)=28-7x\\\\3x^2-5x-28=0\\\\D=(-5)^2+4\cdot3\cdot28=361\\\\x_{1,2}=\frac{5\pm\sqrt{361}}{2\cdot3}=\frac{5\pm19}{6}\\\\x_1=-\frac{7}{3}, \; x_2=4$