Question

7x-4(3x-2)<-8

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Answer 1

Решение и ответ:

$\displaystyle 7x-4(3x-2)<-8$

$\displaystyle 7x-12x+8<-8$

$\displaystyle -5x<-8-8$

$\displaystyle -5x<-16$

$\displaystyle x>-16\div(-5)$

$\displaystyle \boxed{x>3.2}$

либо

$\displaystyle \boxed{x\in\left({3.2;+\infty}\right)}$