Question

Помогите найти производные данных функции.

Answer 1

Ответ:

1.

$y' = \frac{(3 + \frac{1}{2 \sqrt{x} }) \sqrt{ {x}^{2} + 2} - \frac{1}{2 \sqrt{ {x}^{2} + 2} } \times 2x \times (3x + \sqrt{x} ) }{ {x}^{2} + 2 } = \\ = \frac{(3 + \frac{1}{2 \sqrt{x} }) \sqrt{ {x}^{2} + 2 } - \frac{x(3x + \sqrt{x}) }{ \sqrt{ {x}^{2} + 2} } }{ {x}^{2} + 2 } = \\ = \frac{3x + \frac{1}{2 \sqrt{x} } }{ \sqrt{ {x}^{2} + 2 } } - \frac{x(3x + \sqrt{x}) }{ \sqrt{ {( {x}^{2} + 2)}^{3} } } = \\ = \frac{6x \sqrt{x} + 1 }{2 \sqrt{x( {x}^{2} + 2)} } - \frac{x(3x + \sqrt{x}) }{ \sqrt{ {( {x}^{2} + 2)}^{3} } }$

2.

$y '= {e}^{ \sin(x) } \cos(x) (x - \frac{1}{ \cos(x) } ) + { e }^{ \sin(x) } \times (1 + {( \cos(x)) }^{ - 2} \times ( - \sin(x)) = \\ = { e }^{ \sin(x) } \times ( \cos(x) (x - \frac{1}{ \cos(x) } ) + (1 - \frac{ \sin(x) }{ { \cos }^{2}(x) } ))$

3.

$y '= \frac{1}{ ln(3) \times \frac{1}{ \sqrt{1 - {x}^{4} } } } \times ( - \frac{1}{2} {(1 - {x}^{4}) }^{ - \frac{3}{2} } \times ( - 4 {x}^{3} ) = \\ = \frac{ \sqrt{1 - {x}^{4} } }{ ln(3) } \times \frac{2 {x}^{3} }{ \sqrt{ {(1 - {x}^{4}) }^{3} } } = \frac{2 {x}^{3} }{ ln(3) \times (1 - {x}^{4}) }$