• Предмет: Алгебра
  • Автор: saddyrdyusheevz
  • Вопрос задан 1 год назад

у = -х^2 +4х+5


срочно​

Приложения:

Ответы

Ответ дал: Universalka
1

y=-x^{2}+4x+5\\\\X_{v}=-\frac{4}{-2}=2\\\\Y_{v} =-2^{2} +4*2+5=-4+8+5=9\\\\\boxed{(2 \ ; \ 9)}

Ответ дал: jupiteromg
0

y =  - x^{2} + 4x + 5

Determine the coefficients of the quadratic function a and b.

a =  - 1 \\ b = 4

Find the x-coordinate of the vertex by substituting a = -1; b = 4 into the formula x = -b / 2a.

x =  -  \frac{4}{2 \times ( - 1)}  = 2

Find the y-coordinate of the vertex by calculating the function value for x = 2.

y =  - 2^{2}  + 4 \times 2 + 5 =  - 4 + 8 + 5 = 9

x = 2; y = 9.

(x, y) = (2, 9)

Correct variant is D) 2, 9.

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