Question

Пожалуйста помогите сегодня сделать!!! Заранее спасибо ​

Answer 1

Ответ:

1 задание.

б)

$16x \times 5y = (16 \times 5)xy = 80xy$

в)

$- 9x \times 7 {x}^{3} = ( - 9 \times 7)(x \times {x}^{3} ) = - 63 {x}^{4}$

г)

$- 7.2 {a}^{2} {b}^{3} \times ( - 10 {a}^{3} {b}^{4} ) = ( - 7.2 \times ( - 10))( {a}^{2} \times {a}^{3} )( {b}^{3} \times {b}^{4} ) = 72 {a}^{5} {b}^{7}$

д)

${x}^{2} {y}^{7} \times ( - 4 {x}^{3} {y}^{5} ) = - 4( {x}^{2} {x}^{3} )( {y}^{7} {y}^{5} ) = - 4 {x}^{5} {y}^{12}$

е)

$\frac{14}{27} {a}^{3} {b}^{2} \times \frac{3}{7} ab = ( \frac{14}{27} \times \frac{3}{7} )( {a}^{3} \times a)( {b}^{2} \times b) = \frac{2}{9} {a}^{4} {b}^{3}$

ж)

$- 16 {x}^{3} y \times 0.4 {x}^{5} {y}^{2} = ( - 16 \times 0.4)( {x}^{3} \times {x}^{5} )(y \times {y}^{2} ) = - 6.4 {x}^{8} {y}^{3}$

з)

$10.8 \times 4a = (10.8 \times 4)a = 43.2a$

и)

$- 10b {c}^{3} \times 4 {a}^{2} xc = ( - 10 \times 4)( {c}^{3} \times c)b {a}^{2} x = - 40 {a}^{2} b {c}^{4} x$

к)

$xy \times ( - 3x {y}^{4} ) \times 4 {x}^{7} y = ( - 3 \times 4)(x \times x \times {x}^{7} )(y \times {y}^{4} \times y) = - 12 {x}^{9} {y}^{6}$

л)

$- 8a {c}^{2} \times 4 {a}^{6} \times ( - 7c) = ( - 8 \times 4 \times ( - 7))(a \times {a}^{6} )( {c}^{2} \times c) = - 224 {a}^{7} {c}^{3}$

2 задание.

а)

$( - 16) \times 5 = - 80$

б)

$- 14 {a}^{7} \times 5 {a}^{3} = (-14 \times 5)( {a}^{7} {a}^{3} ) = - 70 {a}^{10}$

в)

$- 14 {a}^{7} \times 5 {b}^{3} = ( - 14 \times 5) = {a}^{7} {b}^{3} = - 70 {a}^{7} {b}^{3}$