Question

Решите уравнение,Алгебра
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Answer 1

$\frac{3}{x - 1} + \frac{1}{1 + x} - \frac{28}{1 - x {}^{2} } = 0 \\ \frac{3}{x - 1} + \frac{1}{1 + x} - \frac{28}{(1 - x)(1 + x)} = 0 \\ \frac{3}{x - 1} + \frac{1}{1 + x} + \frac{28}{(x - 1)(1 + x)} = 0 \\ \frac{3(1 + x) + x - 1 + 28}{(x - 1)(1 + x)} = 0 \\ \frac{30 + 4x}{(x - 1)(1 + x)} = 0 \\ 30 + 4x = 0 \\ 4x = - 30 \\ x = - \frac{15}{2} = - 7.5$