Question

ПАМОГИТЕ ПЖ ВСЕ РЕШИТЬ!!! ​

Answer 1

Ответ:

1) (4a^2 -y)*(y+4a^2)= (4a^2-y)*(4a^2+y)= 16a^4-y^2

2)(0.3b^3+x)*(0.3b^3-x)= 0.09b^6-x^2

3) (1.1c^2+z^2) (z^2-1.1c^2)=(z^2+1.1c^2) (z^2-1.1c^2) = z^4-1.21c^4

4) (21d^2-k^3) (21d^2+k^3) = 441d^4-k^6

5) (5a^3 - 4b^2) (4b^2 +5a^3) = (5a^3 - 4b^2) ( 5a^3 + 4b^2) = 25a^6 - 16b^4

6) (1.9c^4 +6d) (6d - 1.9c^4) = (6d + 1.9c^4) (6d - 1.9c^4) = 36b^2 - 3.61c^8