Question

помогите с алгеброй пожалуйста!​

Answer 1

а) $2cos60^{\circ} - \sqrt{3}sin30^{\circ}*tg45^{\circ}$ $= 2*\frac{1}{2} - \sqrt{3} * \frac{1}{2} * 1 = 1 - \frac{\sqrt{3} }{2}$

б) $6sin60^{\circ} - 2\sqrt{3}ctg60^{\circ} * cos30^{\circ} = 6 * \frac{\sqrt{3} }{2} - 2\sqrt{3} * \frac{\sqrt{3} }{3} * \frac{\sqrt{3} }{2} = 3\sqrt{3} - 2 * \frac{\sqrt{3} }{2} = 3\sqrt{3} - \sqrt{3} = 2\sqrt{3}$

в) $4sin45^{\circ} * tg 30^{\circ} * ctg30^{\circ} - cos45^{\circ} = 4 * \frac{\sqrt{2} }{2} * \frac{\sqrt{3} }{3} * \sqrt{3} - \frac{\sqrt{2} }{2} = 2\sqrt{2} * 1 - \frac{\sqrt{2} }{2} = 2\sqrt{2} - \frac{\sqrt{2} }{2} = \frac{3\sqrt{2} }{2}$

г) $tg60^{\circ} * ctg30^{\circ} - cos180^{\circ} + sin90^{\circ} = \sqrt{3} * \sqrt{3} + 1 + 1 = 3 + 2 = 5$