Question

Срочно!!!Помогите решить!!
3 примера!!

Answer 1

Ответ:

1.

${0.25}^{ {x}^{2} - 4} = {2}^{ {x}^{2} + 1 } \\ {( \frac{1}{4} )}^{ {x}^{2} - 4 } = {2}^{ {x}^{2} + 1} \\ {2}^{ - 2( {x}^{2} - 4)} = {2}^{ {x}^{2} + 1 } \\ - 2 {x}^{2} + 8 = {x}^{2} + 1 \\ - 3 {x}^{2} = - 7 \\ {x}^{2} = \frac{7}{3} \\ x1 = \sqrt{ \frac{7}{3} } \\ x2 = - \sqrt{ \frac{7}{3} } \\ \\ x1 = \frac{ \sqrt{21} }{3} \\ x2 = - \frac{ \sqrt{21} }{3}$

2.

${( \frac{2}{3} )}^{2(x - 1)} \times {( \frac{3}{2}) }^{3(x - 1)} = \frac{2}{3} \\ {( \frac{2}{3} )}^{2(x - 1) - 3(x - 1)} = \frac{2}{3} \\ - (x - 1) = 1 \\ - x + 1 = 1 \\ x = 0$

3.

${3}^{x - 1} = {(2 \times 3)}^{x} \times {2}^{ - x} \times {3}^{x + 1} \\ {3}^{x - 1} \times {2}^{x} \times {2}^{ - x} \times {3}^{x} \times {3}^{x + 1} \\ {3}^{x - 1} = {3}^{x + x + 1} \\ x - 1 = 2x + 1 \\ - x = 2 \\ x = - 2$