Question

помогите пожалуйста сделать 550 номер

Answer 1

Ответ:

sin@(0°) = 0

sin@(π/6)=1/2

sin@(π/4)=√2/2

sin@(π/3)=√3/2

sin@(π/2)=1

sin@(2π/3)=√3/2

sin@(3π/4)=√2/2

sin@(5π/6)=1/2

sin@(π)=0

sin@(3π/2)=-1

cos@(0)= 1

cos@(π/6)= √3/2

cos@(π/4)=1/2

cos@(π/3)=1/2

cos@(π/2)=0

cos@(2π/3)=-1/2

cos@(3π/4)=-√2/2

cos@(5π/6)=-√3/2

cos@(π)=1

cos@(3π/2)=0

tg@(0)=0

tg@(π/6)=√3/3

tg@(π/4)=1

tg@(π/3)=√3

tg@(π/2)=нету

tg@(2π/3)=-√3

tg@(3π/4)=-1

tg@(5π/6)=-√3/3

tg@(π)=0

tg@(3π/2)=нету

ctg@(0)=нету

ctg@(π/6)=√3

ctg@(π/4)=1

ctg@(π/3)=√3/3

ctg@(π/2)=0

ctg@(2π/3)=-√3/3

ctg@(3π/4)=-1

ctg@(5π/6)=-√3

ctg@(π)=нету

ctg@(3π/2)=0