Question

835. 1) |x +1,7|×(2x + 3) = 0;
2) |x - 4|× (2x + 7) = 0;
3)5х-8|×(x-6) = 0.
срочно пожалуйста​

Answer 1

Ответ:

1) Ix+1.7|×(2x+3)=0

Ix+1.7|=0

2x+3=0

x1 = -1.7

x2 = -1.5

2) |x - 4|× (2x + 7) = 0

|x - 4|= 0

2x + 7 = 0

х1 = 4

х2 = -3,5

3) |5х-8|×(x-6) = 0

|5х-8| = 0

(x-6) = 0

х1 = 1,6

х2 = 6