Question

Помогите решить задание

Answer 1

Ответ:

$p=log_{b}2\ \ ,\ \ q=log_{b}3\ \ ,\ \ r=log_{b}5\\\\\\1)\ \ log_{b}6=log_{b}(2\cdot 3)=log_{b}2+log_{b}3=p+q\\\\2)\ \ log_{b}108=log_{b}(2^2\cdot 3^3)=2log_{b}2+3log_{b}3=2p+3q\\\\3)\ \ log_{b}45=log_{b}(3^2\cdot 5)=2log_{b}3+log_{b}5=2q+r$

Answer 2

$1)log_{b}6=log_{b}(2*3)=log_{b} 2+log_{b}3=p+q \\\\2)log_{b}108=log_{b}(4*27)=log_{b}2^{2}+log_{b} 3^{3}=2log_{b}2+3log_{b}3=2p+3q\\\\3)log_{b}45=log_{b}(9*5)=log_{b}3^{2}+log_{b}5=2log_{b}3+log_{b}5=2q+r$