Question

7⁹*49⁸/343⁸
1. 7
2. 6
3. 5
4. 10

Answer 1

$\frac{7^{9} *49^{8} }{343^{8} }=\frac{7^{9}*(7^{2})^{8}}{(7^{3})^{8}}=\frac{7^{9}*7^{16} }{74^{2} }=7^{9+16-24}=\boxed 7$

Answer 2

Объяснение:

$\frac{7^9*49^8}{343^8}=\frac{7^9*(7^2)^8}{(7^3)^8}=\frac{7^9*7^{16}}{7^{24}}=\frac{7^{25}}{7^{24}} =7^1=7.$