Question

Алгебра
Нужно срочно

Answer 1

Ответ:

${3}^{2x + 1} - 4 \times 3x + 1 = 0 \\ ({3}^{x} ) ^{2} \times 3 - 4 \times {3}^{x} + 1 = 0 \: \: \: \: \: {3}^{x} = y \\ {y}^{2} \times 3 - 4y + 1 = 0 \\ 3 {y}^{2} - y - 3y + 1 = 0 \\ y(3y - 1) - (3y - 1) = 0 \\( 3y - 1)(y - 1) = 0 \\ 3y - 1 = 0 \\ y - 1 = 0 \\ y = \frac{1}{3} \: \: \: \: \: \: y = 1$