Question

Найдите корень уравнения
$\frac{2x}{ {x}^{2} - 3} = 1$
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Answer 1

$\frac{2x}{x^{2}-3 } =1\\ \\2x=x^{2} -3\\\\x^{2} -2x-3=0\\\\D=4+12=16\\\\x_{1} =(2+4)/2=3 \\x_{2} = (2-4)/2=-1$