Question

Помогите пожалуйста с #33.11

Answer 1

$(a^2-b^2)^3=a^6-3a^4b^2+3a^2b^4-b^6\\\\(m^2+n^2)^3=m^6+3m^4n^2+3m^2n^4+n^6\\\\(2a^2+b^2)^3=8a^6+12a^4b^2+6a^2b^4+b^6\\\\(x^4-6y^2)^3=x^{12}-18x^8y^2+108x^4y^4-216y^6\\\\(7m^3-n^4)^3=343m^9-147m^6n^4+21m^3n^8-n^{12}\\\\(a^3-\dfrac{1}{3}\, b^2)^3=a^9-a^6b^2+\dfrac{1}{3}a^3b^4-\dfrac{1}{27}\, b^6$

$\Big(0,3x^5-0,5y^2\Big)^3=0,027x^{15}-0,135x^{10}y^2+0,225x^5y^4-0,125y^6\\\\\Big(0,6x^2-\dfrac{1}{2}\, y^3\Big)^3=0,216x^6-0,54x^4y^3+0,45x^2y^6-0,125y^9\\\\\Big(\dfrac{1}{5}\, a^2+0,36^4\Big)^3=\dfrac{1}{125}\, a^6+\dfrac{3}{25}\, a^4\cdot 0,36^4+\dfrac{3}{5}\, a^2\cdot 0,36^8+0,36^{12}$