Question

Решите квадратное уравнение
1) -2х²+5х+3=0
2) х²-5х+3=0

Answer 1

1) -2х²+5х+3=0
2x² - 5х - 3 = 0
D= 25 + 4*3*2 = 25 + 24 = 49 = 7^2
x1 = (5+7)/4 = 12/4 = 3
x2 = (5-7)/4 = - 2/4 = - 1/2 = - 0,5

2) х²-5х+3=0
D= 25 - 4*3 = 25 - 12 = 13
x1 = (5+√13)/2
x2 = (5-√13)/2