Question

Помогите срочно 11 надо​

Answer 1

$\displaystyle -3\frac{1}{5}a^8b(\frac{1}{2}a^3b^8)^4=-\frac{16}{5}a^8b(\frac{1}{2^4}*a^{12}b^{32})=-\frac{2^4*a^8*b*a^{12}*b^{32}}{5*2^4}=\\\\=-\frac{a^{20}*b^{33}}{5}$

$\displaystyle x^{n-2}*x^2*x^{n+2}=x^{n-2+2+n+2}=x^{2n+2}$