Question

lim 4x^2+30x-16
      дробная черта
x->0,5 2x-1

Answer 1

$lim_{xto0,5}frac{4x^{2}+30x-16}{2x-1}=lim_{xto0,5}frac{(2x-1)(2x+16)}{2x-1}=\ lim_{xto0,5}(2x+16)=17$