Question

log_по(x+1) (5-x) > 1

Answer 1

$log_{x+1}5-x>1 \ x+1 neq 1 \ x neq 0 \ left { {{x+1>0,} atop {5-x>0;}} right. left { {{x>-1,} atop {x<5.}} right.$
x∈(-1; 5)
$log_{x+1}5-x>log_{x+1}x+1 \ 5-x>x+1 \ -2x>-4 \ x<2$
x∈(-1; 2)

Ответ: x∈(-1; 2).