Question

решите даю 100 балов

Answer 1

$\displaystyle9x^2-16y^2=(3x)^2-(4y)^2=(3x-4y)(3x+4y)$

$\displaystyle (3x+2y)^2=9x^2+12xy+4y^2$

$\displaystyle (x-3n^2)^3=x^3-9x^2n^2+27xn^4+27n^6$

$\displaystyle 125+8x^6=5^3+(2x^2)^3=(5+2x^2)(25-10x^2+4x^4)$

$\displaystyle 64c^3-8=(4c)^3-2^3=(4c-2)(16c^2+8c+4)$

$\displaystyle (3a-5b)((9a)^2+3a*5b+(5b)^2)=((3a)^3-(5b)^3=27a^3-125b^3$

$\displaystyle 4x^2-4x+1=(2x)^2-2*2x*1+1^2=(2x-1)^2$

$\displaystyle 64x^3-144x^2y+108xy^2-27y^3=\\\\=(4x)^3-3*(4x)^2*(3y)+3*(4x)*(3y)^2-(3y)^3=(4x-3y)^3$