Question

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Answer 1

$\frac{2 - 6x}{3} + \frac{3x - 3}{2} = \frac{x - 3}{6} - 1 \\ 6 \times ( \frac{2 - 6x}{3} + \frac{3x - 3}{2} ) = 6 \times ( \frac{x - 3}{6} - 1) \\ 2(2 - 6x) + 3(3x - 3) = x - 3 - 6 \\ 4 - 12x + 9x - 9 = x - 9 \\ - 5 - 3x = x - 9 \\ - 3x - x = - 9 + 5 \\ - 4x = - 4 \\ x = 1$

$(3x - 6)(1 - 1) = 0 \\ (3x - 6) \times 0 = 0 \\ 0 = 0 \\ x∈( - \infty . + \infty )$

подходят все значения x