Question

sin²60 ° + cos²60 ° –tg45 ° = 0, sin²45 + cos²45 - ctg45 ° = 0 плиззз помогите​

Answer 1

Ответ:

$\sin {}^{2} (60) + \cos {}^{2} (60) - \tan(45) = 0 \\ \sin {}^{2} (x) + \cos {}^{2} (x) = 1 \\ 1 - \tan(45) = 0 \\ 1 - 1 = 0 \\ 0 = 0 \\ \sin {}^{2} (45) + \cos {}^{2} (45) - \cot(45) = 0 \\ \sin {}^{2} (x) + \cos {}^{2} (x) = 1 \\ 1 - \cot(45) = 0 \\ 1 - 1 = 0 \\ 0 = 0$