Question

$log_{5} (7x+4)- log_{5} (2x-1)=1$

Answer 1

log5(7x+4)-log5(2x-1)=1
log5(7x+4)-log5(2x-1)=log 5 5
ОДЗ 7x+4>0 x>-4/7
2x-1>0
x>1/2
7x+4/2x-1=5
7x+4=10x-5
3x=9
x=3