Question

Найдите x если , log4 x =log2 3 + log2 корень 2/3

Answer 1

log₄x = log₂3 + log₂ $frac{ sqrt{2} }{3}$
log₄x = log₂ 3*$frac{ sqrt{2} }{3}$
log₄x = log₂ $sqrt{2}$
log₄x = 1/2
x = 2