Question

помогите пожалуйста срочно!!!!!

Answer 1

Ответ:

a)

$f'(x) = 3 {x}^{2} + 6x + 3 \\ \\ 3 {x}^{2} + 6x + 3 = 0 \\ {x}^{2} + 2x + 1 = 0 \\ {(x + 1)}^{2} = 0 \\ x = - 1$

b)

$f'(x) = 3 {x}^{2} - 12x + 12 \\ \\ 3 {x}^{2} - 12x + 12 = 0 \\ {x}^{2} - 4x + 4 = 0 \\ {(x - 2)}^{2} = 0 \\ x = 2$