• Предмет: Алгебра
  • Автор: nikitacalov9
  • Вопрос задан 3 года назад

помогите решить примеры ​

Приложения:

Ответы

Ответ дал: Miroslava227
1

Ответ:

1.

 {6}^{2}  - 3 \times  {2}^{3}  = 36  - 3\times 8 = 36 - 24 = 12

2.

 {( - 3 \frac{1}{2} )}^{2}  +  {( - 3)}^{3}  =  {( -  \frac{7}{2}) }^{2}  - 27 =  \\  =  \frac{49}{4}  - 27 =  \frac{49 - 54}{4}  =  -  \frac{5}{4}  =  - 1.25

3.

 {( - 8)}^{2}  \times   {( -  \frac{3}{8}) }^{2}  = 64 \times  \frac{9}{64}  = 9

4.

 {z}^{8}  \times   {z}^{5}  \times  {( {z}^{7} )}^{2}  =  {z}^{8 + 5}  \times  {z}^{2 \times 7}  =  \\  =  {z}^{13}  \times  {z}^{14}  =  {z}^{27}

5.

 \frac{ {y}^{8}  \times  {y}^{5} }{ {y}^{4} }  =  {y}^{8 + 5 - 4}  =  {y}^{9}  \\

6.

 {( - 5xyz)}^{3}  =  - 125 {x}^{3}  {y}^{3}  {z}^{3}

7.

 - 4 {x}^{5}  {y}^{2}  \times 3x {y}^{4}  =  - 12 {x}^{5  + 1}  {y}^{2 + 4}  =  \\  =  - 12 {x}^{6}  {y}^{6}

8.

 {( -  \frac{1}{3} a {b}^{3} )}^{3}  \times  {(81 {a}^{5} b)}^{1}  =  -  \frac{1}{27}  {a}^{3}  {b}^{9}  \times8 1 {a}^{5} b =  \\  =  - 9 {a}^{8}  {b}^{10}

9.

3 \frac{3}{7}  {x}^{5}  {y}^{6}  \times ( - 2 \frac{1}{3}  {x}^{5} y) ^{2}  =  \\  =  \frac{24}{7}  {x}^{5}  {y}^{6}  \times  {( -  \frac{7}{3}) }^{2}  {x}^{10}  {y}^{2}  =  \\  =  \frac{24}{7}  \times  \frac{49}{9}  {x}^{15}  {y}^{8}  =  \frac{168}{9}  {x}^{15}  {y}^{8}  = 18 \frac{2}{3}  {x}^{15}  {y}^{8}

10.

 \frac{ {36}^{3}  \times  {6}^{4} }{ {2}^{10} \times  {3}^{10}  }  =   \frac{ {( {6}^{2} )}^{3}  \times  {6}^{4} }{ {2}^{10}  \times  {3}^{10} } =  \\  =  \frac{ {6}^{6}  \times  {6}^{4} }{ {(2  \times 3)}^{10} }  =  \frac{ {6}^{10} }{ {6}^{10} }  = 1

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