Question

2x^2+3x+1<0

-x^2+9 ≤0

Answer 1

1) x= [-1; -1/2]
2) x= [-бесконечность, -3], [3, +бесконечность]

Answer 2

Объяснение:

1) 2х^2+3×+1<0

2×^2+2×+×+1=0

2×(×+1)+×+1=0

(×+1)(2×+1)=0

×+1=0

2×+1=0

×1=-1

×2=1/2

Или

2×^2+3×+1<0

Д=3^2-4×2×1=9-8=1

×1=-3+√1/2×2=-2/2×2=-1/2

×2=-3-√1/2×2=-4/2×2=-2/2=1