Question

z(z-10)>(3-z)²
СРОЧНО​

Answer 1

$z(z - 10) > (3 - 2)$

${z}^{2} - 10z > {1}^{2}$

${z}^{2} - 10z = > 1$

${z}^{2} - 10 - 1 > 0 \\ {z}^{2} -1 0z - 1 = 0 \\ z = 5 + \sqrt{26} \\ z = 5 - \sqrt{26}$

$(z - (5 - \sqrt{26} )) \times (z - (5 + \sqrt{26} ) > 0$

$\binom{2 - 5 - \sqrt{26 > 0} }{2 - 5 + \sqrt{26 > 0} }$