Question

Здравствуйте, помогите, пожалуйста ​

Answer 1

$Sin(6\pi+t)=\frac{8}{17}\\\\Sint=\frac{8}{17}\\\\Cost=\sqrt{1-Sin^{2}t } =\sqrt{1-(\frac{8}{17})^{2}}=\sqrt{1-\frac{64}{289} }=\sqrt{\frac{225}{289} } =\frac{15}{17}\\\\tg(\pi+t)=tgt=\frac{Sint}{Cost}=\frac{8}{17}:\frac{15}{17}=\frac{8}{17}*\frac{17}{15} =\frac{8}{15}\\\\\boxed{tg(\pi+t)=\frac{8}{15}}$