Question

помоги решить систему:
3^x * 2^y=72;
3^x+2^y=17

Answer 1

3^x*2^y=72
3^x+2^y=17
3^x=u
2^y=v
uv=72
u+v=17
u=17-v
(17-v)v=72
v2-17v+72=0
v12=(17+-корень(17*17-4*72))/2=(17+-1)/2=9 8
2^y=8
y=3
3^x=9
x=2
2^y=9
y=log2 9
3^x=8
x=log3 8

Answer 2

3^x=9 x=2

Answer 3

2^y=8 y=3