Question

1. Найдите значение выражения cos 30 ° + cos 40 ° + cos 50 ° + ... + cos 150 °.

А) 1

Б) 0

В) невозможно определить

Г) √3/2

Answer 1

Ответ:

$1)\ \ cos30^\circ +cos40^\circ +cos50^\circ +\cdots +cos150^\circ =\\\\=(cos30^\circ +cos150^\circ )+(cos40^\circ +cos140^\circ )+\cdots +(cos80^\circ +cos100^\circ )+cos90^\circ =\\\\=2\cdot \underbrace{cos90^\circ }_{0}\cdot cos60^\circ +2\cdot \underbrace {cos90^\circ }_{0}\cdot cos50^\circ +\cdots +2\cdot \underbrace {cos90^\circ }_{0}\cdot cos10^\circ +\underbrace {cos90^\circ }_{0}=0$

$2)\ \ \Big(tg\dfrac{9\pi}{4}+tg(\dfrac{5\pi}{2}-a)\Big)^2+\Big(ctg\dfrac{5\pi}{4}+ctg(\pi -a)\Big)^2=\\\\\\=\Big(tg(2\pi +\dfrac{\pi}{4})+tg(\dfrac{\pi}{2}-a)\Big)^2+\Big(ctg(\pi +\dfrac{\pi}{4})-ctga\Big)^2=\\\\\\=\Big(\underbrace {tg\dfrac{\pi}{4}}_{1}+ctga\Big)^2+\Big(\underbrace {ctg\dfrac{\pi}{4}}_{1}-ctga\Big)^2=\Big(1+ctga\Big)^2+\Big(1-ctga\Big)^2=\\\\=1+2ctga+ctg^2a+1-2ctga+ctg^2a=2+2ctg^2a=2(1+ctg^2a)=\\\\\\=2\cdot \dfrac{1}{sin^2a}=\dfrac{2}{sin^2a}$