Question

Даю 100 Баллов!!! 3 Задания по алгебре. Прошу

Answer 1

Ответ:

$(x + 7 {)}^{2} - (x - 4)(x + 4) = 23 \\ {x}^{2} + 14x + 49 - ( {x}^{2} - 16) = 23 \\ {x}^{2} + 14x + 49 - {x}^{2} + 16 = 23 \\ 14x + 65 = 23 \\ 14x + 65 - 23 = 0 \\ 14x + 42 = 0 \\ x + 3 = 0 \\ x = - 3$

Answer 2

1a) (y- 3)² = y² - 2 * y * 3 + 3² = y² - 6y + 9

1б) (4x + 1)(4x - 1) = (4x)² - 1² = 16x² - 1

1в) 64 + y³ = 4³ + y³ = (4 + y)(16 - 4y + y²)

1г) (x + 5)(x² - 5x + 25) = x³ + 5³ = x³ + 125

3) (x + 7)² - (x - 4)(x + 4) = 23

x² + 14x + 49 - (x² - 16) = 23

x² + 14x + 49 - x² + 16 = 23

14x = 23 - 49 - 16

14x = - 42

x = - 3

4) (x + 1)² - (x - 1)² = x² + 2x + 1 - (x² - 2x + 1) = x² + 2x + 1 - x² + 2x - 1 = 4x