Question

умоляю пишите ели 100 проц знаете

Answer 1

$\frac{4a^{2}-4a+1 }{6a^{2}-a-1 }=\frac{4(a-0,5)^{2} }{6(a-0,5)(a+\frac{1}{3})}=\frac{2(a-0,5)}{3(a+\frac{1}{3})}=\frac{2a-1}{3a+1}\\\\\\\frac{2*(-5\frac{1}{3})-1 }{3*(-5\frac{1}{3}) +1} =\frac{-2*\frac{16}{3}-1 }{-3*\frac{16}{3}+1 }=\frac{-10\frac{2}{3}-1 }{-16+1}=\frac{-11\frac{2}{3}}{-15}=\frac{35}{3}*\frac{1}{15}=\boxed{\frac{7}{9}}\\\\\frac{7}{9} *9=\boxed7$