Question

Найдите производную функции f(x)=2tgx-5x²

Answer 1

Ответ:

$f(x) = 2tgx - 5x ^{2} =$

$= f'(x) = \frac{d}{dx} (2tgx - 5x ^{2} ) =$

$= f'(x) = \frac{d}{dx} (2tgx) + \frac{d}{dx} ( - 5 x^{2} ) =$

$= f'(x) = 2tg - 5 \times 2x =$

$f'(x) = 2gt - 10x$