Question

x²+2x+1=1
9-x²=0
(x-3)(x+2)=0
решите пж​

Answer 1

Ответ:

$1.x {}^{2} + 2x + 1 = 1 \\ x {}^{2} + 2x = 0 \\ x(x + 2) = 0 \\ x = 0 \: \: \: : \: \: \: x = - 2$

$2.9 - x { }^{2} = 0 \\ x {}^{2} = - 9 \\ x =+- 3$

$3.(x - 3)(x + 2) = 0 \\ x {}^{2} + 2x - 3x - 6 = 0 \\ x {}^{2} - x - 6 = 0$

по теореме Виета:

$x_1 + x_2 = 1 \\ x_1 \times x_{2} = - 6 \\ x_1 = 3 \\ x_2 = - 2$