Question

64
Разложите на множители трехчлены (32.13-32.14):
32. 13. 1) 5х2 + 20x + 20;
2) 2x2 - 12х + 18;
3) -3х2 + 18х - 27;
4) -2у2 - 16y - 32;​

Answer 1

Ответ:32.13 1) =5(x^{2} +4x+4)=5(x+2)^{2}

3) =-3*(x^{2}-6x+9 )=-3(x-3)^{2}

5) =6*(x^{2} +2x+1)=6*(x+1)^{2}

32.14 1) =a*(a^{2} +2a+1)=a*(a+1)^{2}

3) =c^{2} *(c^{2}-4c+4 )=c^{2} *(c-2)^{2}

5) =frac{1}{9} a*(1-8b+16b^{2} )=frac{1}{9} a*(1-4b)^{2}

Answer 2

1)   5х² + 20x + 20 = 5·(x²+ 4x + 4) = 5·(x+2)² = 5(x+2)(x+2)

2)   2x² - 12х + 18 = 2·(x²- 6x + 9) = 2·(x-3)² = 2(x-3)(x-3)

3)   -3х² + 18х - 27 = -3·(x²- 6x + 9) = -3·(x-3)² = -3(x-3)(x-3)

4)   -2у² - 16y - 32 = ​ -2·(y²+ 8y + 16) = -2·(y+4)² = -2(y+4)(y+4)