Question

Даю 100 баллов!!!!!За спам и неправильные ответы бан!​

Answer 1

Ответ:

981

1.

$15 + 5x \leqslant x \\ 4x \leqslant - 15 \\ x \leqslant - \frac{15}{4} \\ \\ 4x \leqslant a \\ x \leqslant \frac{a}{4} \\ \\ = > a = - 15$

2.

$- 9y + 27 > 3 \\ - 9y > - 24 \\ y < \frac{24}{9} \\ y < \frac{8}{3} \\ \\ 3y < a \\ y < \frac{a}{3} \\ \\ = > a = 8$

3.

$14z + 40 < 41 \\ 14 z < 1 \\ z < \frac{1}{14} \\ \\ 7z < a \\ z < \frac{a}{7} \\ \\ = > a = \frac{1}{2}$

4.

$63 - 10t \geqslant 65 \\ - 10t \geqslant 2 \\ t \leqslant - \frac{2}{10} \\ t \leqslant - \frac{1}{5} \\ \\ 5t \leqslant a \\ t \leqslant \frac{a}{5} \\ \\ = > a = - 1$

982.

1.

$\frac{4}{7} + 13x \geqslant 10x + 3\frac{4}{7} \\ 3x \geqslant 3 \\ x \geqslant 1 \\ \\ 2.5x + a \geqslant 1 - 0.5x \\ 3x \geqslant 1 - a \\ x \geqslant \frac{1 - a}{3} \\ \\ \frac{1 - a}{3} = 1 \\ 1 - a = 3 \\ a = - 2$

2.

$19 \frac{2}{9}y - 40 < 20y - 55 \\ 19 \frac{2}{9} y - 20y < - 15 \\ - \frac{7}{9} y < - 15 \\ y > 15 \times \frac{9}{7} \\ y > \frac{135}{7} \\ y > 19 \frac{2}{7}$

$\frac{2}{9} y + 7 < y + a \\ - \frac{7}{9} y < a - 7 \\ y > - \frac{9}{7} (a - 7) \\ y > - \frac{9}{7} a + 9$

$- \frac{9}{7} a + 9 = \frac{135}{7} \\ - \frac{9}{7} a = \frac{135 - 63}{7} \\ - \frac{9}{7} a = \frac{72}{7} \\ a = \frac{72}{7} \times ( - \frac{7}{9} ) = - 8$

Answer 2

Ответ:

$981.\ 1)\ \ 15+5x\leq x\ \ \to \ \ 5x-x\leq -15\ \ ,\ \ 4x\leq -15\\\\4x\leq a\ \ \ \Rightarrow \ \ \ \underline {\ a=-15\ }\\\\2)\ \ -9y+27>3\ \ \to \ \ \ 27-3>9y\ \ ,\ \ 9y<24\ \ ,\ \ 3y<8\\\\3y<a\ \ \ \Rightarrow \ \ \underline {\ a=8\ }\\\\3)\ \ 14z+40<41\ \ \to \ \ \ 14z<1\ \ ,\ \ 7z<0,5\\\\7z<a\ \ \ \Rightarrow \ \ \ \underline {\ a=0,5\ }\\\\4)\ \ 63-10t\geq 65\ \ \to \ \ 63-65\geq 10t\ \ ,\ \ -2\geq 10t\ \ ,\ \ 10t\leq -2\ \ ,\ \ 5t\leq -1\\\\5t\leq a\ \ \Rightarrow \ \ \ \underline {\ a=-1\ }$

$982.\ 1)\ \ \dfrac{4}{7} +13x\geq 10x+3\dfrac{4}{7}\ \ ,\ \ 3x\geq 3\\\\2,5x+a\geq 1-0,5x\ \ \to \ \ \ 3x\geq 1-a\\\\1-a=3\ \ ,\ \ \underline {\ a=-2\ }\\\\2)\ \ 19\dfrac{2}{9}\, y-40<20y-55\ \ \to \ \ \ 20y-\dfrac{173}{9}\, y>55-40\ ,\ \ \dfrac{7}{9}\, y>15\\\\\dfrac{2}{9}\, y+7<y+a\ \ \to \ \ y-\dfrac{2}{9}\, y>7-a\ \ ,\ \ \ \dfrac{7}{9}\, y>7-a\\\\7-a=15\ \ ,\ \ \underline{\ a=-8\ }$