Question

(1,1x + 1,1co
8x - 16 < 0,​

Answer 1

{1,1х+1,1<=0  

{8х-16<0  

{1,1х<=-1,1  

{8х<16  

{х<= - 1  

{х<2

Ответ :х€ (-бесконечности ;-1]