Question

СРОЧНО! ДАЮ 35 БАЛЛОВ!​

Answer 1

Ответ:

Объяснение:

1)

$A = 5~mA\\T = 0.04~s\\\nu = \dfrac1T = \dfrac1{0.04} = 25~Hz$

2)

$\nu = \dfrac c \lambda = \dfrac{3*10^8}{250} = 1\,200\,000~Hz$

3)

$F_A = IBl\sin\alpha \Rightarrow I = \dfrac{F_A}{Bl\sin\alpha} =\dfrac{20}{10*0.4*\sin 90^\circ} = 5~A$

4)

$F_L = qvB\sin\alpha = 1.6*10^{-19} * 10^6 * 1 * \sin 90^\circ = 1.6 * 10^{-13}~N$

5)

$\begin{cases}F_L = qvB\sin\alpha\\F = ma = m\dfrac {v^2} R\end{cases} \Rightarrow F_L = F \Rightarrow qvB\sin\alpha = m\dfrac {v^2} R \Rightarrow B = \dfrac{mv}{Rq\sin\alpha} \\\\B = \dfrac{9.1 * 10^{-31} * 3.5 * 10^6}{0.004 * 1.6 * 10^{-19}*\sin90^\circ} \approx 0.005~Tl$

6)

$\begin{cases}F_A = IBl\sin\alpha\\F = mg \end{cases} \Rightarrow F_A = F \Rightarrow IBl\sin\alpha = mg \Rightarrow I = \dfrac{mg}{Bl\sin\alpha}\\I = \dfrac{3 * 9.8}{20*1*\sin90^\circ} = 1.47~A$