Question

Реши уравнения 4/40+y+16/40=31/40+6/40

Answer 1

Решение.

$\bf \dfrac{4}{40} + y + \dfrac{16}{40} = \dfrac{31}{40} + \dfrac{6}{40}$

$\bf \dfrac{20}{40} +y = \dfrac{37}{40}$

$\bf y = \dfrac{37}{40} - \dfrac{20}{40}$

$\bf y = \dfrac{17}{40}$

Проверка.

$\bf \dfrac{4}{40} + \dfrac{17}{40} + \dfrac{16}{40} = \dfrac{31}{40} + \dfrac{6}{40}$

$\bf \dfrac{37}{40} = \dfrac{37}{40}$ - верно!

Ответ: $\bf y = \dfrac{17}{40}$