Question

Надо решить производную помогите​

Answer 1

Ответ:

Пошаговое объяснение:

y'=(-25x+8)' = (-25x)' +(8)' = -25*1 +0=-25

y' = (-12x+3)' = -12

y' = (-6)' = 0

y' = (16x⁷ -13x⁵ +6x⁴)' = 16*7x⁶ -13*5x⁴ +6*4x³ = 112x⁶ -65x⁴ +24x³

$\displaystyle y'= (\frac{1}{x} +\sqrt{x} )' =(x^{-1})'+(x^{1/2})'= -\frac{1}{x^2}+ \frac{1}{2\sqrt{x} }$

$\displaystyle y'=(\frac{4}{x}-2\sqrt{x} )' = -\frac{4}{x^2} -\frac{1}{\sqrt{x} }$

$\displaystyle y'=(-x^2+2x^7-\frac{1}{3x} )' =-2x +14x^6 -\frac{1}{3x^2}$

$\displaystyle y' = (16x^3-\frac{1}{3x} +3\sqrt{x} )' = 48x^2+\frac{1}{3x^2}+\frac{3}{2\sqrt{x} }$

$\displaystyle y'=(x\sqrt[3]{x} +3x^6-\frac{1}{4x^6} )' = (x^{4/3})'+(3x^6)'-(\frac{1}{4} x^{-6})' =$

$\displaystyle =\frac{4}{3} x^{1/3}+3*6x^5-(\frac{1}{4}* (-6)x^{-7}) =\frac{4\sqrt[3]{x} }{3} +18x^5+\frac{3}{2x^7}$