Question

Знайти значення виразу
(b3+1)(b6-b+1)-b9-b при b=1,7

b3 - в 3 степені

Answer 1

(3+1)(6−+1)−19−

(6−+1)⋅3+1(6−+1)−19−

(6−+1)⋅3+1(6−+1)−19−

9−14+13+1(6−+1)−19−

9−14+13+1(6−+1)−19−

9−14+3+1(6−+1)−19−

9−14+3+1(6−+1)−19−

9−14+3+6−+1−19−

9−14+3+6−+1−19−

9+6−14+3−+1−19−

9+6−14+3−+1−19−

6−14+3−+1−

6−14+3−+1−

6−14+3−2+1