Question

Найдите производные функции y=f(x)

Answer 1

Ответ:

1.

1

$f'(x) = \frac{1}{x} + \cos(x)$

2

$f'(x) = 3 {e}^{x} - 5 {x}^{4}$

2.

1

$f'(x) = ( {x}^{3} ) '\times {2}^{3x} + ( {2}^{3x} )' \times {x}^{3} = \\ = 3 {x}^{2} \times {2}^{3x} + ln(2) \times {2}^{3x} \times 3 \times {x}^{3} = \\ = 3 {x}^{2} \times {2}^{3x} (1 + x ln(2) )$

2

$f'(x) = \frac{( log_{2}(x))' \times 2x - (2x) '\times log_{2}(x) }{4 {x}^{2} } = \\ = \frac{ \frac{1}{x ln(2) } \times 2x - 2 log_{2}(x) }{4 {x}^{2} } = \\ = \frac{1}{4 {x}^{2} }( \frac{2}{ ln(2) } - 2 log_{2}(x) ) = \frac{1}{2 {x}^{2} ln(2) } - \frac{ log_{2}(x) }{2 {x}^{2} }$

3.

1

$f'(x) = \frac{1}{2} {x}^{ - \frac{1}{2} } + ln(5) \times {5}^{x} - \frac{1}{ \cos {}^{2} (x) } = \\ = \frac{1}{2 \sqrt{x} } + ln(5) \times {5}^{x} - \frac{1}{ \cos {}^{2} (x) }$

2

$f'(x) = ln(2) \times {2}^{x} \times ln(x) + \frac{1}{2} \times {2}^{x} = \\ = {2}^{x} ( ln(2) \times ln(x) + \frac{1}{2} )$