Question

I=2A
R=3 OM
t= 150
Q-?

Q=500Дж
1=5 A
R=2 OM
t-?

I=3 A
U= 200 B
t=5c
A-?

А=500Дж
t=100
P-?

I=0,5A
U=180 B
P-?

Answer 1

Ответ:

Объяснение:

$Q = I^2Rt = 4*3*150 = 1800~J\\\\t = \dfrac{Q}{I^2R} = \dfrac{500}{5^2*2} = 10~s\\\\A = UIt = 200*3*5 = 3000~J\\\\P = \dfrac A t = \dfrac{500}{100} = 5~W\\\\P = UI = 180*0.5 = 90~W$