Question

Помогите пж даю 40 балов алгебра 7 класс

Answer 1

1)

$6x^2-x=0\\x(6-x)=0\\x = 0; 6$

2)

$y^2+8y=0\\y(y+8)=0\\y =-8;0$

3)

$a^3-17a^2=0\\a^2(a-17)=0\\a=0;17$

Answer 2

Ответ:

${6x}^{2} - x = 0 \\x(6x - 1) = 0 \\x = 0 \\6x - 1 = 0 \\6x = 1 \\ x = \frac{1}{6}$

${y}^{2} + 8y = 0 \\ y(y + 8) = 0 \\ y = 0 \\y + 8 = 0 \\ y = - 8$

${a}^{3} - 17 {a}^{2} = 0 \\ {a}^{2}(a - 17) = 0 \\ {a}^{2} = 0 \: \: \: \: \: \: a = 0 \\ a - 17 = 0 \\ a = 17$